Mechanical engineering: PRACTICE PROBLEMS
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Showing posts with label PRACTICE PROBLEMS. Show all posts
Showing posts with label PRACTICE PROBLEMS. Show all posts

Wednesday, December 2, 2009

PRACTICE PROBLEMS

PRACTICE PROBLEMS

1. What are measurement standards?

ans. Standards are objects of known size, quantity, roughness, etc. These standards are used to calibrate and verify measuring instruments. As a result, measured values are more accurate.

2. What effect will temperature variation have on precision measurements?

ans. Temperature control during measurement is important because as materials are heated they expand. Each material expands at a different rate. This leads to distortion of parts and measuring devices that results in measurement errors.

3. How can a vernier scale provide higher accuracy?

ans. A vernier scale uses a second elongated scale to interpolate values on a major scale.

4. What are dimensional tolerances, and what are their primary uses?

ans. Dimensional tolerances specify the amount a dimension may vary about a target value. These are supplied by a designer to ensure the correct function of a device. If these tolerances are controlled the final product will work as planned.

5. Why is an allowance different from a tolerance?

ans. A tolerance is the amount a single dimension can vary. An allowance is an intentional difference between two dimensions to allow for press fits, running fits, etc.

6. What are fits?

ans. There are standard for different types of fits (e.g. press fit, running clearance). These specify the allowance of two parts, so that they may be made separately and then joined (mated) in an assembly.

7. What is the difference between precision and accuracy?

ans. Precision suggests a limit of technology, accuracy is the ability to achieve a value consistently. These are often interchanged because we are usually concerned with the accuracy when producing precision parts.

8. If a steel ruler expands 1% because of a temperature change, and we are measuring a 2" length, what will the measured dimension be?

ans. If we assume that only the steel rule expands, and not the steel part, we can calculate,


9. Draw the scales for a vernier micrometer reading 0.3997".





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